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Shah Jignesh
http://www.mediafire.com/view/?4er1332gmsy5ohc


Download ebook: [Get] Software Testing Life Cycle & Concepts
Very good ebook on software testing for freshers.
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Shah Jignesh Gtu Computer Engineering It Books
really helpful. ..........
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Shah Jignesh
oye......wether apllication o data ni link send kr jaldi...............
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Shah Jignesh Crack Aptitude Test
https://www.facebook.com/groups/madhav/


A gROuP FoR aLL Kind Of cOmPetiTiVe ExAMs
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Shah Jignesh Crack Aptitude Test
https://www.facebook.com/SyndicateBankClerkInreviewAspirants


Who want to appear in Syndicate Bank Exams
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Shah Jignesh Crack Aptitude Test
1200 men can construct a wall of length 1500metres in 30days. In how many days can half the previous strength construct 1800 metres of wall working 1/3 rd more time per day than in the previos case
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Konik Pokar

1) If 1200 Men Construct Whole 1800m Wall By Takinh 1/3rd more Time Per Day Then Previous Case Then It Will Take Time Of 27 Day To Construct 1800m Wall
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Konik Pokar

2) If 1200 Men Construt 300m Wall Of 1800m (1500m Wall Constructed Previously) Then It Will Take Time Of 4.5 Day More To Construct 300m Wall Total Wall 1500 + 300 = 1800 And Total Time Taken Is 30 + 4.5 = 34.5 Days
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Jay Kamdar

6 day more than previous case.. (36 days)...
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Anjul Meid

54 days is the answer
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Shah Jignesh Competitive Exams Awareness
For GRE Preparation Download This Book...
GRE Preparation Book
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Shah Jignesh Competitive Exams Awareness
Combined Graduate Level (Tier II) Examination, 2012
Last Date of Application->Apr. 20, 2012
Exam Date-> Sep. 15, 2012 - Sep. 16, 2012
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Shah Jignesh Competitive Exams Awareness
IUCAA (Inter-University Centre for Astronomy and Astrophysics) - NCRA (National Centre for Radio Astrophysics) Admission Test - INAT 2012
Last Date of Application-> Sep. 16, 2012
Exam Date-> Jan. 7, 2013 - Jan. 8, 2013
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Shah Jignesh Competitive Exams Awareness
Graduate Aptitude Test in Engineering (GATE) 2013
Last Date of Application-> Sep. 30, 2012
Exam Date->Jan. 20, 2013
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Shah Jignesh Competitive Exams Awareness
Xavier Admission Test (XAT) 2013
Last Date of Application->Nov. 30, 2012
Exam Date-> Jan. 6, 2013
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Shah Jignesh Competitive Exams Awareness
Symbiosis National Aptitude Test (SNAP) 2012
Last Date of Application->Nov. 20, 2012
Exam Date-> Dec. 16, 2012
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Shah Jignesh Competitive Exams Awareness
Common Admission Test (CAT) 2012
Last Date of Application-> Sep. 19, 2012
Exam Date-> Oct. 11, 2012 - Nov. 6, 2012
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Shah Jignesh Competitive Exams Awareness
NMIMS Management Aptitude Test (NMAT) 2013----Last Date of Application-> Sep. 26, 2012 and Exam Date-> Oct. 11, 2012
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Shah Jignesh Competitive Exams Awareness
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Shah Jignesh Crack Aptitude Test
100! ends with how many zeros?
(a) 22
(b) 23
(c) 24
(d) 25
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Joydip Panchal

@priya 24
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Shah Jignesh

100/20=5 and 20/5=24 so 20+4=24 is ans
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Hothi Sagar

no one 0 because........its ends with '!'.......
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Jay Kamdar

y? 100 / 20?
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Shah Jignesh Crack Aptitude Test
Cathy has six pairs of black socks and six pairs of white socks in her drawer.

In complete darkness, and without looking, how many socks must she take from the drawer in order to be sure to get a pair that match?
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Shah Jignesh

Answer: 3 In complete darkness, and without looking, how many socks must she take from the drawer in order to be sure to get a pair that match?
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Jay Kamdar

yup 3 ..
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Shah Jignesh Crack Aptitude Test
How many rectangles are there in a 4×6 grid of squares ?
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Shah Jignesh

{ m(m+1)/2 } * { n(n+1)/2 } for any m×n grid squares.. so through this 210 is the ans
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Shah Jignesh Crack Aptitude Test
Total Number Of 5 digit numbers of the form xyzyx where x>y is:
1)350
2)360
3)380
4)390
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Shah Jignesh

Sol-> 1<X<8 0<Z<9 when x is 1,y is 2 to9 x=2,y is 3 to 9 so on....... the total number of ways=(8+7+6+_ _ _ _+1)*10=360
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Jay Kamdar

x lies between [1,9]...so 1<=x<=9..
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Shah Jignesh Crack Aptitude Test
If 11th January 1997 was a Sunday then what day of the week was on 10th January 2000?
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Shah Jignesh

Soln->Total number of days between 11th January 1997 and 10th January 2000 = (365 – 11) in 1997 + 365 in 1998 + 365 in 1999 + 10 days in 2000 = (50 weeks + 4 odd days) + (52 weeks + 1 odd day) + (52 weeks + 1 odd day) + (1 week + 3 odd days) Total number of odd days = 4 + 1 + 1 + 3 = 9 days = 1 week + 2 days Hence, 10th January, 2000 would be 2 days ahead of Sunday i.e. it was on Tuesday.
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Jay Kamdar

tuesday...
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Shah Jignesh Crack Aptitude Test
What day of the week was on 10th June 2008?
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Shah Jignesh

Sol;-> 10th June 2008 = 2007 years + First 5 months up to May 2008 + 10 days of June 2000 years have 0 odd days. Remaining 7 years has 1 leap year and 6 ordinary years2 + 6 = 8 odd days So, 2007 years have 8 odd days. No. of odd days from 1st January 2008 to 31st May 2008 = 3+1+3+2+3 = 12 10 days of June has 3 odd days. Total number of odd days = 8+12+3 = 23 23 odd days = 3 weeks + 2 odd days. Hence, 10th June, 2008 was Tuesday.
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Shah Jignesh Crack Aptitude Test
(2^1096 + 2^2248 + 2^2n) find the value of n so that the value will be perfect square

(a)2011 (b)2012 (c)2010 (d)2008

Answer with ur approach...
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Shah Jignesh

sol> 2 series is 2,4,6,8.................then 2^1096 give last digit 6......2^2248 gives last digit 6 then............................................................................... now through option if 2^4022 then last digit8.................if 2^4024 then last digit 6........if 2^4020 then last digit 6 and for 2^4016 then last digit 6................................................................................ then trying to sum with all 3 numbers =sum of their last digit 6+6+8 is only number give last digit 0..................................which may be perfect square..............................................................................and for other case 6+6+6=last digit 8 will never perfect square..............thats why 2011 is the ans
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Shah Jignesh Competitive Exams Awareness
http://spipa.gujarat.gov.in:->Sardar Patel Institute of Public Administration

http://spipa.gujarat.gov.in
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Shah Jignesh

Official Websight Of SPIPA
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Admin

If you are preparing for UPSC or you want to become IAS,IPS.Visit SPIPA.!
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Shah Jignesh Crack Aptitude Test
8,6,17,14,35,30,71,?,143
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Konik Pokar

62
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Konik Pokar

(8 * 2) + 1 = 17, (17 * 2) + 1 = 35, (35 * 2) + 1 = 71, (71 * 2) + 1 = 143, &&& (6 * 2) + 2 = 14, (14 * 2 ) + 2 = 30, (30 * 2) + 2 = 62
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Joydip Panchal

@konik right!!!
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Shah Jignesh Crack Aptitude Test
100! ends with how many zeros?
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Konik Pokar

0 zeros because there is " ! " at the end
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Joydip Panchal

@konik no....24 zeros....
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Poonam Jangid

HOW THE 24 ZEROS???///
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Joydip Panchal

@poonam 100/5 = 20 then again 20/5 = 4 then again 4/5 = 0..add 20 + 4 + 0 = 24 zeros....
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Joydip Panchal

@poonam logis is divide n by 5 and then again ans by 5 until we get 0..then sum of all ans is your number of end zeros...
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