Sol;-> 10th June 2008 = 2007 years + First 5 months up to May 2008 + 10 days of June 2000 years have 0 odd days. Remaining 7 years has 1 leap year and 6 ordinary years2 + 6 = 8 odd days So, 2007 years have 8 odd days. No. of odd days from 1st January 2008 to 31st May 2008 = 3+1+3+2+3 = 12 10 days of June has 3 odd days. Total number of odd days = 8+12+3 = 23 23 odd days = 3 weeks + 2 odd days. Hence, 10th June, 2008 was Tuesday.